5.1 What is the colour of the solution giving rise to the spectrum shown in Figure 5.2?

The absorption band in Figure 5.1ST stretches from 1000 to 500 nm, meaning that the red and significant portion of the green parts of the incident light are absorbed, so solutions of [VO(H2O)5]2+ have a characteristic blue colour.

 

Figure 5.1ST. UV-vis-NIR spectrum of 0.1 M [VO(H2O)5]2+.

 

5.2

(a) Calculate the absorbance of peaks that have 50%, 10% and 1% transmission.

(b) Calculate the %transmission for peaks with an absorbance of 2, 3 and 4.

 

  • For 50% transmission, It /I0 = 0.5, so the absorbance A = −log10(0.5) = 0.30. For 10% transmission, A = −log10(0.1)= 1.00, and for 1% transmission, A = −log10(0.01) = 2.00. (These values show the non-linearity of the transmission scale.)
  • An absorbance value of 2 corresponds to 1% transmission, an absorbance value of 3 corresponds to 0.1% transmission and 4 to 0.01% transmission. These values indicate why absorption spectra get very noisy when A is greater than 3, as there are very few photons arriving at the detector.

 

 

5.3 Convert the following wavelength values to their corresponding wavenumber (cm−1) units. 1000 nm, 600 nm, 400 nm, 250 nm. (A useful conversion is the value in nm = 107/cm−1)

1000 nm = 10000 cm−1 (1000 nm = 107/10000cm−1)

600 nm = 16667 cm−1 (16700 cm−1 to three significant figures)

400 nm = 25000 cm−1

250 nm = 40000 cm−1

5.4 Predict which one of the following complexes will have the more intense d-d transitions: cis-[Co(en)2F2]+ or trans-[Co(en)2F2]+ (en = H2NCH2CH2NH2)

d-d transitions are forbidden by the orbital selection rule (Δl = 1) and the bands associated with them are therefore weak. If there is a centre of symmetry (inversion centre) then the Laporte (parity) selection rule which also makes the d-d transitions forbidden is also operative. As trans-[Co(en)2F2]+ has a centre of symmetry whereas cis-[Co(en)2F2]+ does not, this indicates the latter will have the more intense d-d bands.

5.5 What sort of coordination environments would be best for a commercial pigment based on d-d transitions in a transition metal complex?

The molar absorptivity (εmax) is greatest for compounds without an inversion centre. Therefore, amongst the common geometries for transition metal complexes a tetrahedral coordination environment would be the best as this would give the maximum colour per metal centre based on the d-d transitions. To achieve the highest colour density per metal centre, charge transfer bands would be preferable.

5.6 Calculate εmax for the most intense bands in the other spectra in Figure 5.10.

The molar absorptivities, εmax, in units of dm3 mol−1 cm−1 are given in red in the spectra in Figure 5.6ST.

 

 
Figure 5.6ST Electronic absorption spectra of aqueous solutions of the first row transition metals, showing the εmax values in red.

The concentration of the saturated solution of MnCl2 is assumed to be 3 M. The peak with negative absorbance in this spectrum at 10500 cm−1 in this spectrum is due to an overtone or combination band of water, and because of the very high concentration of the MnCl2 there is less H2O in the sample beam than the reference beam. This is also the cause of the missing data below 9000 cm−1.

 

5.7 The spectrum of [TiCl6]3− has an absorption at 769 nm, that of [TiF6]3− at 518 nm and [TiBr6]3− at 877 nm. Calculate Δoct (in cm−1) for each of these, and comment on the values.

Each of these complexes is Ti3+, and so has a d1 configuration. As there is only one spin-allowed transition for d1 configurations, Δoct can be read straight from the spectral data. Δoct is usually presented in cm−1units, and the values to three significant values are given below.

[TiBr6]3− at 877 nm, 11400 cm−1

[TiCl6]3− 769 nm, 13000 cm−1

[TiF6]3− 518 nm, 19300 cm−1

This corresponds to the order of the ligands in the spectrochemical series (see Section 5.5.3.1)

5.8 Use the spectra of [Ni(H2O)6]2+ and [Ni(en)3]2+ (en = ethylenediamine, or 1,2-diaminoethane) in Figure 5.20 to determine Δoct for these two complexes. Comment on the values obtained.

Both [Ni(H2O)6]2+ and [Ni(en)3]2+ are octahedral Ni2+ complexes with a d8 configuration with three spin-allowed transitions. In the case of octahedral d8, Δoct corresponds to the lowest energy d-d transition. However, some care needs to be exercised as these are not always observable, but as three clear bands with appropriate molar absorptivity values are observed in both spectra, it is reasonable in this case to determine the value of Δoct.

Figure 5.8ST Electronic absorption spectra of [Ni(H2O)6]2+ and [Ni(en)3]2+.

 

In Figure 5.8ST the first peak in the spectrum of [Ni(H2O)6]2+ is at ca. 8500 cm−1 and that for [Ni(en)3]2+ is at 11250 cm−1. Therefore, Δoct for [Ni(H2O)6]2+ is 8500 cm−1, and Δoct for [Ni(en)3]2+ is 11250 cm−1. This is the order of the ligands in the spectrochemical series.

This assignment could be checked with the use of a d8 Tanabe-Sugano diagram.

5.9 The spectrum of [Rh(NH3)6]3+ has two d-d transitions at 32800 and 39200 cm−1, and in the spectrum of [Ir(NH3)6]3+ they are at 39800 and 46800 cm−1. Estimate Δoct for these complexes, and compare the values to that of [Co(NH3)6]3+.

[Rh(NH3)6]3+ and [Ir(NH3)6]3+ are Rh3+ (4d6) and Ir3+ (5d6), respectively. As they are 4d and 5d transition elements they are expected to be low spin, and this is confirmed by the presence of two bands in each case. Δoct can be estimated for low-spin d6 complexes by adding a quarter of the difference between the first two spin-allowed transitions to the lower value.

For [Rh(NH3)6]3+ the observed d-d transitions are at 32800 and 39200 cm−1, giving Δoct = 34400 cm−1

For [Ir(NH3)6]3+ the observed d-d transitions are at 39800 and 46800 cm−1, giving Δoct = 41550 cm−1

Δoct for [Co(NH3)6]Cl3 is 23000 cm−1, and the values for [Rh(NH3)6]3+ and [Ir(NH3)6]3+ show that Δoct increases on going from 3d to 4d to 5d. The explanation is that as the principal quantum number n increases, the orbitals become larger so there is a greater difference between the extent of interaction of the t2g and eg metal d orbitals with the ligand orbitals. This increases the energy between the t2g and eg metal d orbitals, and hence increases Δoct.

5.10 When an excess of NCS is added to a solution of [Co(H2O)6]2+, the pale pink solution turns a very deep blue. What does this indicate about the structure of cobalt in the two complexes, and propose a structure for the NCS complex.

There are two changes reported to the d-d transitions when NCS is added to a solution of [Co(H2O)6]2+, the first is that the colour changes from pink to blue, and the second that the intensity changes from pale pink to very deep blue. The first is related to the energy of the transitions and the second to their allowedness, which is dependent on the selection rules. An increase in intensity is usually associated with a relaxation of the selection rules, and for transition metal complexes this is most usually related to the Laporte/parity selection rule, so that the loss of a centre of symmetry (inversion centre) results in greater intensity. As the reaction uses an excess of NCS it can be assumed that there is total ligand exchange to form tetrahedral [Co(NCS)4]2− (NCS can be regarded as a pseudo halide). As there is no inversion centre in tetrahedral complexes the Laporte/parity selection rule is no longer operative so the d-d transitions will be less forbidden and gain intensity. In addition the orbital selection rule (Δl = ±1) is also relaxed as the metal 4p orbitals have the same symmetry as the metal t2 orbitals and can mix, so the transitions are no longer pure d-d. The change in colour from pink for the octahedral complex to blue for tetrahedral complex is in line with a reduction of Δ on going from octahedral to tetrahedral (Δtet = 4/9Δoct). However it is not so simple as there are three spin-allowed transitions for each, but not all are in the visible part of the spectrum. (Spectra of [Co(H2O)6]2+ and [CoCl4]2− are given in Figure 5.56)

5.11 Calculate εmax for the d-d peaks in Figure 5.23, assuming a pathlength of 1 cm.

The molar absorptivities, εmax, can be calculated using the Beer Lambert Law (A= εcl) for the d-d peaks in Figure 5.11ST and are given to two sig. fig in the table below.

 

λmax /cm−1

Abs

εmax /dm3 mol−1 cm−1

1.2 mM [Co(NH3)5ONO]Cl2

20500

0.075

63

 

29000

0.33

280

 

 

 

 

1.2 mM [Co(NH3)5NO2]Cl2

22000

0.11

92

 

30500

2.2

1800

The change in εmax is due to differential effects of the nitrito and nitro ligands on the orbital and Laporte/parity selection rules.


5.11ST Electronic absorption spectra of isomerisation of 1.2 mM solution of [Co(NH3)5(ONO)]Cl2 to [Co(NH3)5(NO2)]Cl2 in 0.1 M HClO4 at 40° C for 90 min. Inserts show spectra of initial and final complexes

5.12 Some iron(II) complexes can be changed reversibly between high-spin and low-spin by changing the temperature because Δ and the electron pairing energy, P, are very delicately balanced. These are known as spin-crossover complexes and the iron(II) examples tend to contain a FeN6 coordination environment. By consideration of the spectrochemical series suggest ligand donor atoms which might be used to produce spin-crossover complexes of Fe(III).

As the ligand field splitting parameter, Δ, is larger for iron(III) than iron(II), to obtain spin-crossover conditions for iron(III), weaker field ligands than those containing nitrogen will be required. This indicates halogen ligands or those containing sulfur. As a result of this some of the most common iron(III) spin-crossover complexes contain bidentate ligands with two sulfur donor atoms such as dithiocarbamate (S2CNR2 or S2CNRR¢).

5.13 In general, transition metals in high oxidation states become weaker oxidising agents as the Group is descended, as we have seen with [ReO4] and [MnO4] . Predict a colour and position of the LMCT band in the UV-vis spectrum for the [MoO4]2− and the [MoS4]2− ions.

[CrO4]2− is yellow with a charge transfer transition at 27000 cm−1 (370 nm), so for [MoO4]2− the analogous charge transfer transition will be at higher energy, so [MoO4]2− is predicted to be colourless/white. The lowest energy charge transfer transition is at 42700 cm−1 and it is a white/colourless solid. As S2− is easier to reduce than O2− the charge transfer will be at a lower energy in [MoS4]2− than [MoO4]2−, and is therefore expected to be coloured. The first charge transfer transition in [MoS4]2− is at 21300 cm−1 and as a result it is a dark orange colour.

5.14 Predict the form of the UV-vis spectrum of CdTe.

What colour would you expect of rutile, TiO2, that had been chemically modified so that its band gap absorption had a tail that was just in the visible region?

From the pattern in Figure 5.26 it is expected that the absorption edge of CdTe will be at longer wavelength/lower energy than that of CdSe. The band gap for CdTe is ca. 860 nm, which means that it absorbs all visible light and is therefore a black material. CdTe finds use in thin film photovoltaic solar cells, including in some very large photovoltaic power stations.

Pure TiO2 is colourless as the band gap absorption edge is in the UV part of the spectrum, but when it is chemically modified or doped, the absorption edge can move to lower energy so that the tail is in the visible, and this will give rise to a yellow colouration (see Figure 5.1).

5.15 The first charge transfer absorption band observed in the UV-vis spectrum of the [CoF6]2− anion is at 28300 cm−1 calculate an optical electronegativity for Co(IV). A new compound was isolated and proposed to contain either the [CoCl6]2− or [CoCl6]3− anion. Its first charge transfer band was at 36000 cm−1. Determine which anion is present in this compound.

Eexp = 28300 cm−1 and the optical electronegativity (copt) from Table 5.4 for F is 3.9, therefore using

Eexp = 30000[χopt(ligand) − χopt(metal)],

χopt(Co4+) = 3.9 − (28300/30000) = 3.0

[CoCl6]2− contains Co4+; χopt(Co4+) = 3.0, χopt(Cl) = 3.0

[CoCl6]3− contains Co3+; χopt(Co3+) = 1.8, χopt(Cl) = 3.0

Eexp(Co3+) = 30000[3.0 – 1.8] = 36000 cm−1

Eexp(Co4+) = 30000[3.0 – 3.0] = 0 cm−1

This analysis indicates that the calculated first LMCT band Co3+ (Eexp(Co3+)) at 36000 cm−1 is in excellent agreement with the experimental observation. Therefore, the new compound contains [CoCl6]3−. The optical electronegativities of Co4+ and Cl are so similar that the first ligand to metal charge transfer transition is at very low (effectively zero) energy. This means that in practice the Cl will reduce the Co4+ (or more intuitively the Co4+ will oxidise the Cl) permanently, rather than transiently.

5.16 The iron(III)-ruthenium(II) analogue of Prussian blue, Fe(III)4[Ru(II)(CN)6]3.18H2O, is dark purple with an IVCT band at 495 nm. What does this tell us about the extent of delocalisation in the two materials?

The presence of an IVCT band indicates that there is delocalisation in the mixed iron(III) and ruthenium(II) Prussian blue analogue. The energy of the IVCT band is inversely proportional to the extent of electron delocalisation between the metal centres, i.e. more delocalisation is expected for lower energy IVCT transitions. Therefore, a shift in energy from 680 nm (14700 cm−1) for Fe(III)[Fe(III)Fe(II)(CN)6].xH2O (Fe4[Fe(CN)6].xH2O) to 495 nm (20200 cm−1) for Fe(III)4[Ru(II)(CN)6].18H2O indicates a greater extent of electronic localisation in the mixed iron ruthenium Prussian blue analogue, which is in fact dark purple. In the dark green all ruthenium analogue the IVCT band is at 1000 nm (10000 cm−1) indicating greater delocalisation. (J. N. Behera, D. M. D’Alessandro, N. Soheilnia and J. R. Long, Chem. Mater. 21 1922 (2009).))

5.17 Why are the solutions of Tb3+ and Yb3+ essentially colourless?

In the spectrum of Tb3+ in Figure 5.17ST all of the transitions are very weak with very small εmax values. Apart from a very very weak peak at 20500 cm−1 there are no bands in the visible part of the spectrum (12500 – 26000 cm−1), although there are peaks at 10250 cm−1 in the NIR and a series of weak peaks starting at 26500 cm−1 in the UV.

In the Yb3+ spectrum there are no peaks in the visible part of the spectrum, although the tail into the UV may contribute a very weak yellow hue to concentrated solutions.

Figure 5.11ST Electronic absorption spectra of f–f transitions in Pr3+, Tb3+, Er3+, and Yb3+ aqueous solutions.

5.18 Determine the spin multiplicity of the atomic fn configurations.

 

fn

Σ

MS

2S+1

name

f0, f14

0

0

1

‘singlet’

f1, f13

½

+½, −½

2

‘doublet’

f2, f12

1

+1, 0, −1

3

‘triplet’

f3, f11

3/2

+3/2, +1/2, −1/2, −3/2

4

‘quartet’

f4, f10

2

+2, +1, 0, −1, −2

5

‘quintet’

f5, f9

5/2

+5/2, +3/2, +1/2, −1/2, −3/2, −5/2

6

‘sextet’

f6, f8

3

+3, +2, +1, 0, −1, −2, −3

7

‘septet’

f7

7/2

+7/2, +5/2, +3/2, +1/2, −1/2, −3/2, −5/2, −7/2

8

‘octet’

 

5.19 Determine the term for total orbital angular momentum L = 4 and total spin angular momentum S = 0.

If L = 4, the total orbital angular momentum is represented by G. If the total spin angular momentum S is 0, then the spin multiplicity, 2S + 1 is 1. Therefore, the term is 1G.

5.20 The allowed terms for d7 are 2H, 2G, 4F, 2F, 2D, 2D, 4P, 2P, identify the ground term.

There is also a very quick and easy way to determine the ground term for any configuration using Hund’s 1st and 2nd rules. For d7, l = 2 so ml = 2, 1, 0, -1, -2. The seven electrons occupy the d-orbitals with parallel spins (to satisfy Hund’s 1st rule) starting on the left with the highest value of ml (to satisfy Hund’s 2nd rule) and working across as shown in Figure 5.20ST.

Figure 5.20ST

ΣμΣ = ½ + ½ + ½ + ½ + ½ − ½ − ½ = 3/2  S = 3/2 \ 2S+1 = 4

Σμl = 2 + 1 + 0 – 1 – 2 + 2 + 1 = 3  \ L = 3 Þ F

Therefore, the ground term is 4F.

The arrangement of electrons in Figure 5.20ST is one of (2L + 1)(2S + 1), i.e. 28 microstates that all have the same energy. This is just the one with the highest value of ML and MS that we are well trained in drawing out as the ground state configuration.

5.21 Sketch the ordering and energy intervals of the levels in the 7F ground terms of Eu3+ and Tb3+.

The 7F term is split by spin-orbit coupling into levels with J = 0 to 6. The ordering is dependent on Hund’s third rule so that for Eu3+ with a 4f6 configuration the 7F0 lies lowest in energy, but for Tb3+ with a 4f8 configuration the 7F6 lies lowest in energy. Application of Eqn 5.4 gives the energy of the levels relative to the terms. It is also important to note that the separation between the levels is given by the Landé interval rule, which states that the energy between two levels is simply λ times the J value of the larger of the two adjacent levels.

A sketch is given in Figure 5.21ST

Figure 5.21ST Ordering of the levels in the 7F ground terms of Eu3+ and Tb3+.

5.22 Calculate the single electron spin-orbit coupling constant,ζ, for Tb3+ using the data in Figure 5.36 and Figure 5.37.

The transition energies and their assignments are given in Figure 5.22ST. The derivedλ values, the Landé interval rule, and ζ = −2λΣ for Tb3+, yields the values in the table below.

Observed transition /cm−1

Difference

/cm−1

Assignment

 

λ / cm−1

ζ / cm−1

20380 cm−1

−1990

5D47F6

 

−332

1990

18390 cm−1

−1230

5D47F5

 

−246

1476

17160 cm−1

−1020

5D47F4

 

−255

1530

16140 cm−1

 

5D47F3

 

 

 

 

Figure 5.22ST Emission spectrum of 12.5 μM Tb3+ dpa complex at 250 nm excitation.

As for Eu3+ there is a spread of values because of the breakdown in the Russell-Saunders approach for high values of J. The literature value of ζ for Tb3+ is 1709 cm−1.

5.23 Determine the ground terms for the other high-spin dn configurations using the spin multiplicity and orbital degeneracy method outlined above (ignore the trailing subscripts). Check these against those in Table 5.6 which have the trailing subscripts for completeness. Repeat the process for tetrahedral terms and check against Table 5.6.

The ground terms for high-spin octahedral and tetrahedral transition metal ions are shown in Figure 5.23ST(a) and Figure 5.23ST(b), respectively. You should note the pattern that dn and dn+5 have the same orbital label, and that the term for dn octahedral is equivalent to the term for d10-n tetrahedral.

Figure 5.23ST(a) Ground terns for high-spin octahedral transition metal ions.

 

 

Figure 5.23ST(b) Ground terms for high spin tetrahedral transition metal ions.

5.24 Calculate the terms for the ground and spin-allowed excited states for octahedral high-spin d7 complexes, and hence identify the number of spin-allowed transitions.

The ground term for d7 with a t2g5eg2 configuration is 4T as there are three unpaired electrons giving a spin multiplicity of f4, and three orbital permutations to give T. There are two spin-allowed excited 4T terms derived from one electron transitions with t2g4eg3 configurations. The two members easiest to spot are shown in the 4T terms below. There is also a spin-allowed two electron transition resulting in a 4A term for the t2g3eg4 configuration. Therefore, there are three spin-allowed transitions for high-spin d7 complexes. The terms shown in Figure 5.24STinclude the trailing subscript for completeness, but identifying these is a long-winded exercise (see simple d2 example in the text), and it is best to look them up in the Tanabe-Sugano diagrams.


Figure 5.24ST Ground and spin-allowed excited terms for octahedral d7 complexes.

5.25 The first two spin-allowed d-d transitions in trans-[CrCl2(H2O)4]+ (Figure 5.44(a)) are at 16510 and 23450 cm−1. Using the d3 Tanabe-Sugano diagram (Figure 5.45) and Lever plot (Figure 5.46) calculateΔ, B and predict the position of the third spin-allowed transition.

As trans-[CrCl2(H2O)4]+ is d3, the first d-d transition at 16510 cm−1 in Figure 5.25ST(a) is equivalent to Δoct.

Figure 5.25ST(a) Electronic absorption spectra of (i) 0.05 M trans-[CrCl2(H2O)4]+ and (ii) 0.15 M [Cr(H2O)6]3+.

However, in order to determine B it is necessary to make use of the d3 Tanabe-Sugano diagram, and/or the Lever plot of ratios of the spin-allowed transition energies. The ratio of the first two spin-allowed transitions at 16510 cm−1 (4T2g ¬ 4A2g) and 23450 cm−1 (4T1g ¬ 4A2g) is 1.420. Using this value and the Lever ratio plot diagram a value for Δ/B of 23.4 can be obtained. This also shows that the only realistic assignment of these two features is to the first two spin-allowed transitions. This ratio can also be obtained by measuring ratio directly (i.e. with a ruler) from the Tanabe-Sugano diagram. These workings are shown in the figures below.

Figure 5.25ST (b) Tanabe-Sugano diagram for octahedral d3 and (c) Lever plot of ratios of transition energies for d3/d8, including workings for trans-[CrCl2(H2O)4]+.

As the gradient of the 4T2g ¬ 4A2g transition is 1.00, this gives a value of E/B = 23.4 for the 4T2g ¬ 4A2g transition, and hence a value of 705 cm−1 for B (The B values are reported to the nearest 5 or 10, given the accuracy of the process). To check this value against the second transition it is necessary to draw a vertical line at 23.4 on either the Tanabe-Sugano diagram (Figure 5.25ST(b), or the Lever diagram (Figure 5.25(c)) and determine where this intercepts the 4T1g line. This gives an E/B value of 33.2 for the 4T1g ¬ 4A2g transition, and a B value of 705 cm−1. The third spin-allowed transition is predicted to be at E/B = 52.0 from both of the diagrams, and this corresponds to 36700 cm−1, which is masked by the charge transfer transition in the UV part of the spectrum.

The Δoct value for trans-[CrCl2(H2O)4]+ 16510 cm−1 is smaller than that for [Cr(H2O)6]3+ (17080 cm−1) as expected given the position of Cl and H2O in the spectrochemical series. The values of B of 706 cm−1 for trans-[CrCl2(H2O)4]+ is essentially the same as that for [Cr(H2O)6]3+ (705 cm−1) using the same methodology, indicating a similar level of covalency in [Cr(H2O)6]3+ compared to trans-[CrCl2(H2O)4]+.

5.26 Use the d8 Tanabe-Sugano diagram (Figure 5.49) and the three observed d-d transitions in [Ni(H2O)6]2+ at 8550, 14480 and 25370 cm−1 and in [Ni(en)3]2+ at 11280, 18350, 29040 cm−1 (Figure 5.48) to calculate Δoct for [Ni(H2O)6]2+, and for [Ni(en)3]2+. Using the ratio of the first and third transitions with either the d8 Tanabe-Sugano diagram (Figure 5.49) or the Lever plot of transition energy ratios (Figure 5.46) calculate B for [Ni(H2O)6]2+ and [Ni(en)3]2+. The d-d spectrum of [Ni(NH3)6]2+ has peaks at 10750, 17500 and 28200 cm−1, use these to calculate Δoct and B for this complex. Comment on the values of Δoct and how the values of B compare to the free ion value of 1042 cm−1 in Table 5.9.

The spectra of [Ni(H2O)6]2+ and [Ni(en)3]2+ are shown in Figure 5.26ST(a)

Figure 5.26ST(a) Electronic absorption spectra of [Ni(H2O)6]2+ and [Ni(en)3]2+.

For d8 octahedral complexes the value of Δoct is given by the first spin-allowed d-d transition. So Δoct is 8550 cm−1 for [Ni(H2O)6]2+, 10750 cm−1 for [Ni(NH3)6]2+, and 11280 cm−1 for [Ni(en)3]2+. The ratio of the first and third transitions is 2.967 for [Ni(H2O)6]2+, 2.623 for [Ni(NH3)6]2+and 2.574 for [Ni(en)3]2+. Using the T1g(P)/T2g(F) line on the Lever ratio plot (Figure 5.26ST(c)) gives Δ/B of 9.2 for [Ni(H2O)6]2+, 12.2 for [Ni(NH3)6]2+and 12.9 for [Ni(en)3]2+. The workings for [Ni(H2O)6]2+ are shown in red, those for [Ni(NH3)6]2+ in blue and those for [Ni(en)3]2+ in green. As Δoct is equivalent to the first d-d transition in d8 complexes this means the gradient of the 3T2g line is 1.0 and that therefore E/B is 9.2 for [Ni(H2O)6]2+, 12.2 for [Ni(NH3)6]2+and 12.9 for [Ni(en)3]2+. These values can then be used to obtain B, which is 930 cm−1 for [Ni(H2O)6]2+, 880 cm−1 for [Ni(NH3)6]2+, and 875 cm−1 for [Ni(en)3]2+. (The B values are reported to the nearest 5 or 10, given the accuracy of the process.) The Δ/B ratios can also be used to check the B values using the E/B values for the third transition. These are 27.3 for [Ni(H2O)6]2+, 32.0 for [Ni(NH3)6]2+and 33.1 for [Ni(en)3]2+, which give B values of 930, 880 and 875, respectively. The B values and E/B data can also be used to predict the position of the second spin-allowed transitions. For [Ni(H2O)6]2+ B is 930 cm−1 and E/B is 15.3 for the second transition indicating a transition energy of 14230 cm−1. For [Ni(NH3)6]2+ B is 880 cm−1 and E/B is 19.5, giving a transition energy of 17160 cm−1. For [Ni(en)3]2+ B is 875 cm−1 and E/B is 20.5 implying a transition energy of 17940 cm−1. These values are in reasonable agreement with the experimental ones, especially given possibility of the spin-forbidden transitions discussed in Example 5.26, and the accuracy of using the charts.

The values of Δoct are in line with the position of the ligands in the spectrochemical series. The values of B are all lower than the free ion value of 1042 cm−1. This is an example of the nephelauxetic effect (see Section 5.15), and the greater reduction of B for the NiN6 coordination environment indicates a greater extent of covalency in the bonding than in the Ni(OH2)6 coordination environment. The Δoct and B values for [Ni(NH3)6]2+ and [Ni(en)3]2+ are similar, with the Δoct and B values of [Ni(en)3]2+ being slightly larger and smaller, respectively, than those of [Ni(NH3)6]2+.

Figure 5.26ST (b) Octahedral d8 Tanabe-Sugano diagram, and (c) Lever (ratio of transition energies) plot for d3/d8. Analysis shown for [Ni(H2O)6]2+, [Ni(NH3)6]2+ and [Ni(en)3]2+.

5.27 Use Figure 5.54 and/or Figure 5.55 and the data in Figure 5.21 ([Co(NH3)6]Cl3, 21070, 29460 cm−1; [CoCl(NH3)5]Cl2, 18810, 27540 cm−1) to calculate Δoct and B for [Co(NH3)6]Cl3 and [CoCl(NH3)5]Cl2. Compare these values with those in Example 5.9.

The electronic absorption spectra of [Co(NH3)6]Cl3 and [CoCl(NH3)5]Cl2 are shown in Figure 5.27ST(a)

Figure 5.27ST(a) Electronic absorption spectra of [Co(NH3)6]Cl3 and [CoCl(NH3)5]Cl2.

For [Co(NH3)6]Cl3, the first two spin-allowed in these low-spin d6 complexes are at 21070 and 29460 cm−1 giving a ratio of 1.398. In [CoCl(NH3)5]Cl2 they are at 18810, 27540 cm−1 giving a ratio of 1.464. These are shown in the plots below.

Figure 5.27ST (b) Octahedral d6 Tanabe-Sugano diagram, and (c) Lever (ratio of transition energies) plot for low-spin d6. Analysis shown for [Co(NH3)6]Cl3 and [CoCl(NH3)5]Cl2.

For [Co(NH3)6]Cl3 (shown in red) a ratio of 1.398 indicates a Δ/B value of 36.85, and E/B values of 33.9 and 47.3. In conjunction with the transition energies of 21070 and 29460 cm−1 this gives values of B of 620 and 623 cm−1, which can be taken to be 620 cm−1. Using this in conjunction with Δ/B of 36.85, implies a value of Δoct of 22850 cm−1.

For [CoCl(NH3)5]Cl2 (shown in green) the ratio of 1.464 indicates a Δ/B value of 30.7, with E/B values of 27.85 and 40.8 for the 18810 and 27540 cm−1 transitions, yielding B values of 675 and 675 cm−1. Using the Δ/B value of 30.7 and B of 675 cm−1 gives a value of Δoct of 20720 cm−1.

Using the more simple approach in Example 5.9 values of 23000 cm−1 and 21000 cm−1 were obtained for [Co(NH3)6]Cl3 and [CoCl(NH3)5]Cl2, respectively, compared to 22850 and 20720 cm−1 using this more sophisticated approach. Therefore, the simple method gives acceptable values of Δoct.

5.28 Calculate εmax for the peaks in Figure 5.56(b), and compare these with the values in Figure 5.56(a) and Table 5.1. The literature value of εmax for [CoCl4]2− is 580 dm3 mol−1 cm−1, what does your value indicate about the extent of reaction between [Co(H2O)6]2+ and HCl to form [CoCl4]2−? As dn tetrahedral configurations can be covered by d10-n octahedral Tanabe-Sugano diagrams, use the d3 Tanabe-Sugano diagram (Figure 5.45 and Appendix 4) and the reported values of Δtet (3120 cm−1) and B (710 cm−1) for [CoCl4]2− to assign the features in Figure 5.56(b). It should be noted that for both the octahedral and tetrahedral Co2+ complexes the lowest energy transitions were outside the range of conventional spectrometers, and a detailed analysis using the Tanabe-Sugano diagrams was necessary to confirm the assignments.

The electronic absorption spectra of the 0.2 M [Co(H2O)6]2+ solution, and that diluted tenfold by 8 M HCl to give a 0.02 M solution of [CoCl4]2− are shown in Figure 5.28ST(a).

 

Figure 5.28ST(a) Electronic absorption spectra of (i) 0.2 M [Co(H2O)6]2+ and (ii) 0.02M [CoCl4]2− (tenfold dilution of solution (i) with 8 M HCl).

Assuming 1 cm pathlengths, the values of εmax are given below.

 

 

λmax /cm−1

Abs

εmax /dm3 mol−1 cm−1

0.2 mM [Co(H2O)6]2+

8000

0.29

1.5

 

19500

0.94

4.7

 

21350

0.64

3.2

 

 

 

 

0.02 mM [CoCl4]2−

14500

1.36

68

 

15100

1.29

65

 

15950

0.89

45

 

The εmax values for [Co(H2O)6]2+ are consistent with those for an octahedral complex in Table 5.1. The experimental values for [CoCl4]2− derived from Figure 5.28ST(a) are about an order of magnitude smaller than the literature values for [CoCl4]2−. Despite the spectrum being dominated by the spectral features of [CoCl4]2− the low values indicate that the equilibrium between [Co(H2O)6]2+ and [CoCl4]2− still lies a long way over to the left-hand side (Figure 5.28ST(b). The weaker peak at ca 19000 cm−1 is indicative of some remaining octahedral complexes, but as it is at lower energy than the initial peak it is most likely due to a mixed Cl/H2O environment. In the analogous reaction using NCS discussed in Self Test 5.10, it is necessary to add acetone to the reaction mixture to drive the equilibrium to the right-hand side by removing water from the cobalt coordination sphere.

 

Figure 5.28ST(b) Equilibrium between [Co(H2O)6]2+ and [CoCl4]2− in the presence of excess HCl.

With Δtet = 3120 cm−1 and B = 710 cm−1, Δ/B = 4.39, and this vertical line is shown in the d3 Tanabe-Sugano diagram in Figure 5.28ST(c). Using this line, the transition energies can be predicted using the horizontal lines, and these, together with the assignments, are shown in the table below. There are no g subscripts on the terms as there is no inversion centre in tetrahedral complexes.#

 

E/B

E /cm−1

Assignment

4.39

3120

4T2 (F)¬ 4A2

7.65

5430

4T1 (F) ¬ 4A2

20.5

14550

4T1 (P)¬ 4A2

Therefore, the complex peak at ca. 15000 cm−1 in Figure 5.28ST(a) can be assigned to the 4T1 (P) ¬ 4A2 transition, as the other two transitions are predicted to be below the energy range of the experiment, and are essentially in the IR part of the spectrum. The lowest energy transition at 3100 cm−1 is equivalent to Δtet, as expected for tetrahedral d7 (and also octahedral d3 and d8 and tetrahedral d2). As in the case of the spectrum of saturated MnCl2 (Figure5.57), the negative absorbance features around 10000 cm−1 are due to the overtones and combination bands of water not ratioing out because of the high concentration of HCl present which results in a slightly smaller amount of water in the sample compared to the reference beam.

 

Figure 5.28ST(c)Tanabe-Sugano diagram for d7 tetrahedral complexes adapted from the d3 octahedral Tanabe-Sugano diagram by removal of g subscripts, and expanding over area of interest.

Although it is tempting to assign the fine structure on the 15000 cm−1 band in Figure 5.28ST(a) to vibrational fine structure (as in the spectrum of [MnO4]), it is thought to be due to spin-forbidden transitions to the 2E, 2T1, (and to a lesser extent the 2T2 and 2A1) terms derived from the 2G atomic term which are in close proximity to the 4T1g (P) term for the Δ/B ratio of 4.39, as shown in Figure 5.28ST(c).

The very substantial increase in molar absorptivity for the tetrahedral complex implies that some of the selection rules have been relaxed. There is no reason to think that the spin selection rule has been relaxed, therefore this must be down to the orbital and Laporte components of the dipole selection rule. The Tdpoint group does not contain an inversion centre, so the Laporte selection rule is no longer operative, and the d orbital labels are just e and t2. The metal dxy, dxz and dyz orbitals also have the same symmetry as the metal p orbitals (t2) and this mixes some p character into these d orbitals which relaxes the orbital selection rule (Δl = ± 1) so that the d-d transitions are no longer pure d to d, but d to d/p.

 

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