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Return to Maths for Chemistry 3e Student Resources
Chapter 21 Multiple choice questions
Quiz Content
*
not completed
.
Using integration by parts, find:
y
=
∫
x
3
e
5
x
d
x
.
y
=
e
5
x
5
(
x
3
−
3
x
2
)
+
c
correct
incorrect
y
=
2e
5
x
125
(
5
x
−
1
)
+
c
correct
incorrect
y
=
3e
5
x
25
(
x
2
−
2
x
)
+
c
correct
incorrect
y
=
e
5
x
625
(
125
x
3
−
75
x
2
+
30
x
−
6
)
+
c
correct
incorrect
*
not completed
.
Using integration by parts, find:
y
=
∫
x
2
ln
3
x
d
x
.
y
=
x
3
9
(
ln
3
x
−
1
)
+
c
correct
incorrect
y
=
x
3
9
(
3
ln
3
x
−
1
)
+
c
correct
incorrect
y
=
x
3
9
(
ln
3
x
+
1
)
+
c
correct
incorrect
y
=
x
3
9
(
−
ln
3
x
+
1
)
+
c
correct
incorrect
*
not completed
.
Using integration by parts, find:
y
=
∫
e
4
x
sin
3
x
d
x
.
y
=
e
4
x
25
(
4
sin
3
x
−
3
cos
3
x
)
+
c
correct
incorrect
y
=
25
e
4
x
(
4
sin
3
x
−
3
cos
3
x
)
+
c
correct
incorrect
y
=
e
4
x
25
(
3
cos
3
x
−
4
sin
3
x
)
+
c
correct
incorrect
y
=
25
e
4
x
(
3
cos
3
x
−
4
sin
3
x
)
+
c
correct
incorrect
*
not completed
.
Using integration by substitution, find:
y
=
∫
x
7
(
2
x
8
−
5
)
6
d
x
.
y
=
(
2
x
8
−
5
)
7
42
+
c
correct
incorrect
y
=
(
2
x
8
−
5
)
7
112
+
c
correct
incorrect
y
=
x
8
(
2
x
8
−
5
)
7
42
+
c
correct
incorrect
y
=
x
8
(
2
x
8
−
5
)
7
112
+
c
correct
incorrect
*
not completed
.
Using integration by substitution, find:
y
=
∫
x
2
4
x
3
−
7
d
x
.
y
=
ln
4
x
−
x
3
14
+
c
correct
incorrect
y
=
1
4
x
2
−
7
x
+
c
correct
incorrect
y
=
ln
(
4
x
3
)
−
3
x
3
7
+
c
correct
incorrect
y
=
ln
(
4
x
3
−
7
)
12
+
c
correct
incorrect
*
not completed
.
Using integration by substitution, find:
y
=
∫
cos
(
x
)
x
d
x
.
y
=
sin
(
x
)
+
c
correct
incorrect
y
=
2
sin
(
x
)
+
c
correct
incorrect
y
=
1
sin
(
x
)
+
c
correct
incorrect
y
=
2
sin
(
x
)
+
c
correct
incorrect
*
not completed
.
Using integration by backward substitution, find:
y
=
∫
x
x
+
5
d
x
.
y
=
(
x
+
5
)
+
c
correct
incorrect
y
=
ln
(
(
x
+
5
)
)
+
c
correct
incorrect
y
=
2
3
(
x
+
5
)
3
+
c
correct
incorrect
y
=
2
3
(
(
x
+
5
)
3
−
15
x
+
5
)
+
c
correct
incorrect
*
not completed
.
Calculate the following integral:
y
=
∫
1
x
2
+
4
d
x
.
y
=
1
2
t
a
n
(
2
x
)
+
c
correct
incorrect
y
=
1
2
arctan
(
x
2
)
+
c
correct
incorrect
y
=
−
1
2
cot
(
2
x
)
+
c
correct
incorrect
y
=
1
2
ln
(
x
2
+
4
)
+
c
correct
incorrect
*
not completed
.
Calculate the following integral:
y
=
∫
0
∞
x
3
e
−
4
x
d
x
.
y
=
3
128
correct
incorrect
y
=
3
256
correct
incorrect
y
=
1
2
π
4
correct
incorrect
y
=
π
2
correct
incorrect
*
not completed
.
Calculate the following integral:
y
=
∫
0
π
2
sin
(
4
x
)
sin
(
6
x
)
d
x
.
y
=
π
2
correct
incorrect
y
=
3
π
4
correct
incorrect
y
=
π
4
correct
incorrect
y
=
0
correct
incorrect
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