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Return to Statistical Thermodynamics 2e Student Resources
Chapter 9 Multiple choice questions
Quiz Content
*
not completed
This question is concerned with internal energy modes in the ideal diatomic gas. Which
one
of the following assertions is correct?
Translation energy modes are never affected by the presence of internal energy modes.
correct
incorrect
The Born-Oppenheimer approximation is used to decouple rotational modes from vibrational modes.
correct
incorrect
An energetic collision between two molecules can equilibrate the internal energy modes.
correct
incorrect
If all energy modes are assumed to be separable, we can write for the total energy of molecule
j
:
correct
incorrect
*
not completed
This question concerns the concept of weak coupling and the ways in which molecular energy modes can be factorised. Which
one
of the statements below is correct?
Molecular energy modes can reach thermal equilibrium and be treated as behaving independently if there is zero coupling between them.
correct
incorrect
Weak coupling allows each molecular energy mode to be treated as enjoying its own thermal equilibrium, independent of any of the other molecular modes.
correct
incorrect
If energy modes are separable, the molecular translational partition function can be broken into three parts, one for each independent direction in three dimensions:
q
trs
=
q
trs,x
x
q
trs,y
x
q
trs,z
correct
incorrect
Under the weak coupling assumption, the partition functions in each of three directions of motion,
q
trs,x
and
q
trs,y
and
q
trs,z
, can no longer be considered to be independent.
correct
incorrect
*
not completed
This question concerns the factorisation of internal energy modes and its effect on the canonical partition function Q. Which
one
of the statements below is correct?
The concept of separability allows us to factorise the overall molecular partition function into the following terms:
q
tot
=
q
·
rot
q
·
vib
q
el
correct
incorrect
In contrast to the molecular partition function, the canonical partition function can
not
be written
Q
tot
=
Q
trs
·
Q
rot
·
Q
vib
·
Q
el
correct
incorrect
Internal energy states are intrinsically distinguishable
correct
incorrect
NlnQ
tot
=
N
ln
q
trs
×
N
ln(
q
rot
q
vib
q
el
)
correct
incorrect
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