Skip to main content
United States
Jump To
Support
Register or Log In
Support
Register or Log In
Instructors
Browse Products
Getting Started
Students
Browse Products
Getting Started
Chapter 17 Multiple Choice Questions
Return to Inorganic Chemistry 7e student resources
Chapter 17 Multiple Choice Questions
The Group 17 elements
Quiz Content
*
not completed
.
The halogens have high electron affinity because:
They can accommodate only one electron in their valence shell; therefore the energy required for this process is low.
correct
incorrect
The incoming electron can occupy an orbital of an incomplete valence shell and thus experience strong nuclear attraction.
correct
incorrect
The nuclear attraction to the electrons in their atoms is high and tends to draw new electrons in.
correct
incorrect
*
not completed
.
Find the correct statement:
The Group 17 elements form hydrides that behave as acids in aqueous solutions
correct
incorrect
The Group 17 elements form very stable oxides commonly found in the laboratory
correct
incorrect
The Group 17 elements occur in oxidation states from -1 to +7.
correct
incorrect
*
not completed
.
Why are aqueous fluoride solutions
not
used in the production of fluorine by electrolysis?
because fluorides are insoluble in water
correct
incorrect
because water is oxidized at a much lower potential than F
–
and because any F
2
produced would react rapidly with the water
correct
incorrect
because the electrolysis of water solutions of fluorides would require a prohibitively large amount of water and energy
correct
incorrect
*
not completed
.
Fluorine atoms are small and their electrons are tightly gripped by the nucleus. Therefore, molecular fluorine compounds have:
high polarizabilities and strong dispersion interactions
correct
incorrect
low polarizabilities and strong dispersion interactions
correct
incorrect
low polarizabilities and weak dispersion interactions
correct
incorrect
*
not completed
.
What is the molecular geometry of ClF
3
as predicted by VSEPR?
T-shaped
correct
incorrect
trigonal bipyramidal
correct
incorrect
trigonal planar
correct
incorrect
*
not completed
.
When I
2
is added to a solution containing I
–
, a deep brown colour develops. How can that phenomenon be explained?
I
–
is oxidized to I
2
.
correct
incorrect
I
2
is dissolved in the water.
correct
incorrect
Polyiodides, such as I
3
–
and I
5
–
, are formed.
correct
incorrect
*
not completed
.
Perchlorate is a very weak Brønsted base and a weak Lewis base and is used as a weakly coordinating ion that can be easily displaced from a complex by other ligands. When using the perchlorate ion in this situation, care must be taken because:
The perchlorate ion is a powerful oxidizing agent that can explode unexpectedly and unpredictably.
correct
incorrect
The perchlorate ion is a powerful oxidizing agent that rapidly oxidizes the ligands before complexes are formed for further study.
correct
incorrect
The perchlorate ion is a powerful oxidizing agent that rapidly oxidizes the metal acceptors before complexes are formed for further study.
correct
incorrect
*
not completed
.
In basic solutions chlorine, bromine, and iodine undergo ___________, with the formation of +1 (XO
–
) and ______ species:
comproprionation; +3 (XO
2
–
)
correct
incorrect
reduction; O
2
correct
incorrect
disproportionation; –1 (X
–
)
correct
incorrect
*
not completed
.
The oxidation of molecules and ions by halogen oxoanions increases in the order:
ClO
2
–
< ClO
3
–
< ClO
4
–
correct
incorrect
ClO
4
–
< BrO
4
–
< IO
4
–
correct
incorrect
IO
3
–
< IO
4
–
correct
incorrect
*
not completed
.
Which transition metal fluoride is used in the production of fluorocarbons?
FeF
3
correct
incorrect
CoF
3
correct
incorrect
NiF
2
correct
incorrect
Previous Question
Submit Quiz
Next Question
Reset
Exit Quiz
Review & Submit
Submit Quiz
Are you sure?
You have some unanswered questions. Do you really want to submit?
Back to top
Printed from , all rights reserved. © Oxford University Press, 2024
Select your Country