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Chapter 7 Self-test questions
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Chapter 7 Self-test questions
Rate Constants and Equilibria
Quiz Content
*
not completed
.
A system is made up of a large number of particles that can each exist in three different quantum states 0, 1 and 2, all singly degenerate (
g
= 1), with energies ε
0
= 0 kJ mol
-1
, ε
1
= 6 kJ mol
-1
, and ε
2
= 12 kJ mol
-1
. At a temperature of 320 K, what proportion of the particles will occupy the state 2?
1%
correct
incorrect
10%
correct
incorrect
33%
correct
incorrect
100%
correct
incorrect
*
not completed
.
The vibrational partition function for a molecule of Br
2
(vibrational wavenumber: 323 cm
-1
) can be calculated in the harmonic oscillator approximation. At 500 K, what is
q
vib
?
1
correct
incorrect
108
correct
incorrect
1.65
correct
incorrect
4.3
correct
incorrect
*
not completed
.
For a reaction having a standard free energy change at 298 K of -30 kJ mol
-1
, what is
K
at that temperature?
1.01
correct
incorrect
1.8 x 10
5
correct
incorrect
5.5 x 10
-6
correct
incorrect
30
correct
incorrect
*
not completed
.
A molecular dynamics simulation is carried out for a protein solvated in water, using
NVT
conditions and
T
= 310 K. Two different conformations, A and B, are visited during the simulation. At 1 ps intervals, the structure is assigned to either A or B, and after a simulation length of 24.6 ns, the number of times that conformation A was visited is
n
A
= 420. Assuming that equilibrium has been reached, what is the free energy of B relative to A?
-10.5 kJ mol
-1
correct
incorrect
20.6 kJ mol
-1
correct
incorrect
7.3 kJ mol
-1
correct
incorrect
-10,500 kJ mol
-1
correct
incorrect
*
not completed
.
Enhanced sampling methods are often needed in conjunction with molecular dynamics or Monte Carlo simulations, because…
…they are newer methods so they are expected to yield less approximate results.
correct
incorrect
…for many systems, the transitions needed to reach equilibrium are 'rare events' that barely or never occur with normal sampling.
correct
incorrect
…computer simulation will never lead to the system crossing a transition state, as that is a quantum-mechanical event.
correct
incorrect
…normal sampling methods yield the wrong distribution of structures even if the simulation is long enough that key transitions occur often enough.
correct
incorrect
*
not completed
.
Two candidate drug molecules A and B are being assessed. The free energy perturbation method is used to calculate their relative free energy of solvation in water, and their relative free energy of interaction with the relevant drug-binding site of a protein, in each case at 310 K. The calculations show that converting A to B in water leads to a free energy change of -1.4 kJ mol
-1
, while converting A to B in the protein leads to a free energy change of -8.2 kJ mol
-1
. Compared to A, B can be predicted to:
Bind roughly 10 times more strongly to the protein.
correct
incorrect
Bind roughly 100 times less strongly to the protein.
correct
incorrect
Bind roughly equally strongly to the protein.
correct
incorrect
Bind roughly 10,000 times more strongly to the protein.
correct
incorrect
*
not completed
.
The dimer of nitrogen dioxide, N
2
O
4
, is in equilibrium with NO
2
. The free energy of activation Δ
G
‡
for the dissociation reaction at 298 K is calculated to be 35 kJ mol
-1
. What is
k
dissoc
?
4.4 x 10
6
M
-1
s
-1
.
correct
incorrect
4.4 x 10
6
s
-1
.
correct
incorrect
6.1 x 10
12
s
-1
.
correct
incorrect
0
correct
incorrect
*
not completed
.
Concerning the molecular dynamics simulation for liquid butane described on pp. 113-115 and illustrated in Figs. 7.1 and 7.2, which of the following statements is correct?
The forcefield used suggests that butane should be chiral, since one of the mirror image
gauche
forms is observed more than the other one.
correct
incorrect
Anti
-butane is lower in energy and so it is the only form present at most temperatures.
correct
incorrect
Isomerization of
anti-
butane to each of the two
gauche
forms occurs faster than the direct conversion of the gauche form with θ = 60° to the other gauche form with θ = 300°.
correct
incorrect
At 120 ps, the simulation time is too short to reach any conclusions about free energies in butane.
correct
incorrect
*
not completed
.
M06/6-311G(d) calculations are performed for H
2
, C
2
H
4
and C
2
H
6
. Geometry optimization returns total energies of respectively -1.1686, -78.5301 and -79.7677 hartree (1 hartree = 2625.5 kJ mol
-1
). Vibrational frequencies are computed, and statistical mechanics calculations are performed at 298 K using the rigid rotor, harmonic oscillator approximation, yielding
G
–
G
(0) values of respectively -0.0016, 0.0295 and 0.0528 hartree. What is the predicted Δ
G
° for the hydrogenation of C
2
H
4
?
-24 kJ mol
-1
correct
incorrect
-148 kJ mol
-1
correct
incorrect
-116 kJ mol
-1
correct
incorrect
-3200 kJ mol
-1
correct
incorrect
*
not completed
.
A molecule of nitrogen oxide has a bond length of 1.151 Å. Using
m
N
m
O
/(
m
N
+
m
O
) = μ = 1.240 x 10
-26
kg and σ = 1, calculate the rotational partition function for this molecule at T = 350 K.
12
correct
incorrect
143
correct
incorrect
1
correct
incorrect
56
correct
incorrect
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